I looked through internet and couldn\'t find a clear and concise answer to my question. I want to know what\'ll happen if I drive same strength signals onto the same wire, one of them being logic 1 an
I have a doubt in the generate, my code is: parameter m=1; generate for(i=0; i<m; i=i+1) :loopstart
module fronter ( arc, length, clinic ) ; input [7:0] arc; output reg [7:0] length ; input [1:0] clinic;
I have seen the following used to make state changes in Verilog modules: state <= 开发者_如何转开发2\'b10;
This would make a Verilog module sensitive to a clock and a reset switch being turned on: always @(posedge clk, posedge rst)
I want to convert the data in a 开发者_运维知识库wire to an integer. For example: wire [2:0] w = 3\'b101;
When we use input reg [7:0] ast, f_out; ast === f_out ; ast <= ast + 8\'b00000001; for those opera开发者_如何转开发tions \" === and <= \", Have any time delay been occurred ?
X, Y, Z, T are different jobs. Ex, X = Multiplexer( ... )开发者_JAVA技巧 if ( empty1 ) if ( empty2 )
module stimulus; reg [511:0]FROM_LS; reg CLOCK; reg [2:0]HMIC_CTRL; reg [20:0]BRANCH_CTRL; reg[63:0]TO_IF_ID;
I\'ve encountered in an example for a system verilog code decleration of inputs and outputs for a module without stating their type, e.g log开发者_JAVA百科ic, wire...