Let\'s consider a big file (~100MB). Let\'s consider that the file is line-based (a text file, with relatively short line ~80 chars).
I am trying to get the data from this website: http://www.boursorama.com/includes/cours/last_transactions.phtml?symbole=1xEURUS
With Python 3 I am requesting a json document from a URL. response = urllib.request.urlopen(request) The response object is a file-like object with read and readline method开发者_如何学Cs. Normally
When I push files to the server, then after 60 seconds i get \"urlopen error [Errno 10054]\". I think it\'s because i push large files.
I\'m fairly new to python, (and programming in general), and I\'ve ran into some trouble while writing a program to fetch midi files from the internet. Below is some code that I exp开发者_Python百科ec
I\'m trying to read the source of a website with this code: import urllib2 z=urllib2.urlopen(\'http://skreemr.com/results.jsp?q=said+the+whale&search=SkreemR+Search\')
I us开发者_StackOverflow中文版ed Python\'s urllib2.urlopen and got a 500 error from the server. How do I find the text of the error? I\'m hoping that it has useful information.from urllib2 import urlo
This loop help get some text data from web service: while True: u = urllib2.urlopen(\'http://url/%d.csv\' %inputd)
I\'m using the following code to get data from a website: time_out开发者_JS百科 = 4 def tryconnect(turl, timer=time_out, retries=10):
so i have the code def constructGraph(self,url,doit=5): if doit!=0: m = urllib.request.urlopen(url) 开发者_如何学Cprint(\'test\')
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