I\'ve been reading about Python\'s urllib2\'s ability to open and read directories that are password protected, but even after looking at examples in the docs, and here on StackOverflow, I can\'t get
Hey all, I have a si开发者_如何学Pythonte that looks up info for the end user, is written in Python, and requires several urlopen commands. As a result it takes a bit for a page to load. I was wonderi
Greetings, I have done: import urllib site = urllib.urlopen(\'http://www.weather.com/weather/today/Temple+TX+76504\')
for the following cod开发者_如何学Pythone theurl = \"https://%s:%s@members.dyndns.org/nic/update?hostname=%s&myip=%s&wildcard=NOCHG&mx=NOCHG&backmx=NOCHG\" % (username, password, host
I\'m trying to upload data from a CSV to my app using the devserver: appcfg.py upload_data --config_file=\"DataLoader.py\" --filename=\"data.csv\" --kind=Foo --url=http://localhost:8083/remote_api \"
Below is script that I found on forum, and it is almost exactly what I need except I need to read like 30 different url\'s and print them all together.I have tried few options but script just breaks.
I\'m using urllib2\'s urlopen function to try and get a JSON result from the StackOverflow api. The code I\'m using:
I\'d like to tell urllib2.urlopen (or a custom opener) to use 127.0.0.1 (or ::1) to resolve addresses. I wouldn\'t change my /etc/r开发者_如何学Goesolv.conf, however.
The urllib2 documentation says that timeout parameter was added in Python 2.6. Unfortunately my code base has been running on Python 2.5 and 2.4 platforms.