Extract text from a file object using .read()

I'm trying to read the source of a website with this code:

import urllib2
z=urllib2.urlopen('http://skreemr.com/results.jsp?q=said+the+whale&search=SkreemR+Search')
z.read()
print z
txt = open('music.txt','w')
txt.write(str(z))
txt.close()
for i in open('music.txt','r'):
        if '''onclick="javascript:pageTracker._track开发者_StackOverflow社区Pageview('/clicks/''' in i:
                print i

And all I get for the source code is:

<addinfourl at 51561608L whose fp = <socket._fileobject object at 0x0000000002CCA480>>

It might be an error I don't know?

Does anyone know of a better way to do the job above without putting it into a text file first?

z is a file object. In fact your codes prints the object description. You need to put the result of z.read() inside a variable (or print it directly).

You should do

import urllib2
z=urllib2.urlopen('http://skreemr.com/results.jsp?q=said+the+whale&search=SkreemR+Search')
i = z.read()
print i

.read() does not actually change the state of z. Use z=z.read() instead.

z is the file-like object. str(z) just gives you the representation you're seeing.

You need to keep the string (the contents of the file) that's returned by z.read().

Better yet, just iterate over it directly:

import urllib2
z=urllib2.urlopen('http://skreemr.com/results.jsp?q=said+the+whale&search=SkreemR+Search')
for i in z:
    if '''onclick="javascript:pageTracker._trackPageview('/clicks/''' in i:
        print i

I think you're missing what read does. Try:

data = z.read()
print data
with open('music.txt','w') as txt:
    txt.write(data)

with open('music.txt','w') as out:
    out.write(urllib2.urlopen('http://skreemr.com/results.jsp?q=said+the+whale&search=SkreemR+Search').read()

But this is just the html for the page, you will need to parse it yourself using beautiful soup or lxml