I know you can get the first byte by using int x = number & ((1<<8)-1); or int x = number & 0xFF;
I\'m reading through a book on C++ standards: \"Thinking in C++\" by Bruce Eckel. A lot of the C++ features are explained really well in this book but I have come to a brick wall on something and wh
I have been reading a lot of articles lately about programming practice, design and so forth and was curious about the real performance gains from implementing multiplication as bit shifting.
I have some code that stuffs in parameters of various length (u8, u16, u32) into a u64 with the left shift operator.
Code Taken From: Bytes to Binary in C Credit: BSchlinker The following code I modified to take more than 1 Byte at a time.I modified it, and got it half working and then got really confused on my loo
I have been trying this for long. I have a byte array, which I want to convert to ulong and return the value to another function and that function should get the byte values back.
I want to create a 64-bit barrel shifter in verilog (rotate right for now). I want to know if there is a way to do it without writing a 65 part case statement? Is there a way to write some simple code
I am looking at big code base in C++. There i开发者_JS百科s line mentioned as below int capacity( ) const
DWORDLONG index = ((((DWORDLONG) i.nFileIndexHigh) << 32) | i.nFileIndexLow); Given index, I want to find out what the components of i.file开发者_如何转开发indexhigh and i.fileindexlow are. I
Is there a way to shift left or right without the byte loss, so that the bytes filled are the ones that are beeing taken?
加载中,请稍侯......