Do you know any way to ef开发者_StackOverflow中文版ficient check if overflow/underflow occurs on x86 left shift arithmetically?A good option is to perform an arithmetic shift right after the shift lef
unsigned int command = 4; cout << command; command = (command << 1); cout << command; command 开发者_开发百科= (command << 1);
I have the following hex value store 开发者_如何学Goin a variable: 0x04a8f5 I want to convert the value to:
I\'m looking for a way to represent a set of integers with a bit vector (which would be the characteristic function of that set of integers) and be able to perform bitwise operations on this set.
In C++ I have code like this. static UInt32 rol(UInt32 value, UInt32 bits) { bits &= 31; return ((value << bits) | (value >> (32 - bits)));
This question already has an answer here: Closed 开发者_Python百科11 years ago. Possible Duplicate:
I have a test program like this: int main() { unsigned n = 32; printf(\"ans << 32 = 0x%X\\n\", (~0x0U) << 32);
This question is NOT about \"How do i bitwise permutation\" We now how to do that, what we are looking for is a faster way with less cpu instructions, inspired by the bitslice implementation of sboxes
Is there an algorithm that can be use to subtra开发者_StackOverflow社区ct 1 from a number using only increments (++ in C) and left bitwise shifts (<< in C) ?
I\'m working on a Objective-C program where I\'m getting bitfields over the network, and need to set boolean variables based on those bits.
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