I have something like this in my code: template <typename T> struct A { void Print(); }; template <>
Consider this code: typedef int type1; typedef int type2; template <typename> struct some_trait; template <开发者_如何学编程>
suppose I have a file alpha.h: class Alpha { public: template<typename T> void foo(); }; template<> void Alpha::foo<int>() {}
Why is the following cod开发者_StackOverflow中文版e invalid? template <typename S, typename T>
I\'m writing a logging class that uses a templatized operator<< function. I\'m specializing the template function on wide-character string so that I can do some wide-to-narrow translation before
I have a templated sparse_vector<T> class, and I am also using Boost UBLAS.How would I provide implicit conversions between sparse_vector<double> and boost::numeric::ublas::compressed_vect
I have the following scenario: class my_base { ... } class my_derived : public my_base { ... }; template<typename X>
This compiled on VS 2008, but it seems like non-standard usage of templates. template <class T> class Foo
I\'m writing a simple maths library with a template vector type: template<typename T, size_t N> class Vector {
I am trying to specialize template the following way: template<size_t _1,size_t _2> // workaround: bool consecutive = (_1 == _2 - 1)>
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