I have the following code: typedef vector<int> Vec; typedef vector<Vec> VecOfVec; template<typename Vec>
Given this code: class X { publ开发者_JS百科ic: template< typename T > void func( const T & v );
Here\'s a largely academic exercise in understanding conversion operators, templates and template specializations.The conversion operator template in the following code works for int, float, and doubl
How would one initialize static data members of a template class differently for particular parameters?
Say I have this: template<typename T, int X> class foo { public: voi开发者_Go百科d set(const T &t);
I would like to define a C++ template specialization that applies to all subclasses of a given base class. Is this possible?
I\'ve been messing around with enable_if, and I seem to have stumbled upon some inconsistent behaviour. This is in VS2010. I\'ve reduced it to the following sample.
I have a template, template <typename T> class wrapper, that I would like to specialize based on the existence of typename T::context_type. If typename T::context_type is declared, then the cons
Say I have this开发者_Python百科 template class: template<typename T> class MyClass{ public:
I have a template class with an int and a template te开发者_运维百科mplate parameter. Now I want to specialize a member function:
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