I\'m trying to implement properties with readonly, writeonly and readwrite behaviour. I thought template specialization would be the way to go here, so I tried this:
struct Bar { enum { Special = 4 }; }; template<class T, int K> struct Foo {}; template<class T> struct Foo<T,T::Special> {};
I know this subject should be pretty much dated by now, but I\'m having a tough time with this specific case.
I have a template function that I expect to be templatized for different types at different places. The problem is that I would like to know at compile time if there is an specialization for the given
I\'m building a hashmap class that can have string keys and ints, bools, strings or pointers of different types as its values, and I want it to work. For the program I\'m using it for I create the poi
I have a class Helper: template <typename T, template <typename> E> class Helper { ... }; I have another class template, Exposure, which is to inherit from Helper while passing itself a
My question is w.r.t the following thread : specialize a me开发者_如何学JAVAmber template without specializing its parent
I have a custom logging class that supports iostream-syntax via a templated operator <<: template< class T >
The following code compiles properly. #include <string> template <typename T, typename U> class Container
How to specialize a template defined in some external namespace in the body of my class? Concrete example using BGL which doesn\'t compile:
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