I\'m having compile time trouble with the following code: template <typename T, template <class T, class Allocator = std::allocator<T> > class C>
I am creating a templated class D<N>, with a method (operator(), in this case) that returns different types, depending on the val开发者_开发技巧ue of N.
I want to define a macro that can be invoked in different places (at file scope) in order to create functions that do something.(In the example below the functions just print a message, but of course
Note: this seems to be a repost of a problem: C++ - Overload templated class method with a partial specilization of that method
Let\'s imagine we have several type of elements, and we want to create a \'manager\' for every type of them.The manager takes care of the
I have template <int i> struct a { static void f (); }; with specializations done at different places in the code. How can I call the correct a<i>::f for an i known only at runtime?
Why this doesn\'t work? template <class T> struct Low; template <> struct Low<int> {};//Here I\'m trying to specialize for int开发者_运维百科
I love templates, at least I would if I would understand them ;-). I implemented an overloaded operator using templates. I am now trying to specialise the function calls.
My third question here today ;-), but I am really new to c++ template programming and operator overloading.
##A.hh template<class T> void func(T t) {} template<> void func<int>(int t) {} void func2();
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