Consider the following code: template <typename T> class B { }; template <typename T> B<T> f(T& t)
decltype is supposed to yield the type of its parameter. A comma expression is supposed to have the type of its right hand operand. In the example below all but c2 are false when compiled with VS2010.
For the following code: auto F(int count) -> decltype([](int m) { return 0; }) { return [](int m) { return 0; };
Consider the following code: class A { private: class B {}; public: B f(); }; A a; A::B g() { return a.f(); } The compi开发者_JAVA百科ler rejects this - g cannot return A::B because A::B is priva
Is there开发者_如何转开发 some vendor-specific type inference mechanism in Microsoft Visual C++ 2008, similar to the standardized auto or decltype in C++0x?No, nothing like that, standard nor vendor s
Few minutes ago I\'ve tried to do something like this: #include \"stdafx.h\" #include <iostream>
template<typename T> struct A { auto func() -> decltype(T::func()) { return T::func(); } }; class B : public A<B> {
I want to write a simple adder (for giggles) that adds up every argument and returns a sum with appropriate type.
I have some trouble understanding the need for std::result_of in C++0x. If I understood correctly, result_of is used to obtain the resulting type of invoking a function object with开发者_如何学Go cert
I\'m trying to use C++0x, and in particular lambda expression and decltype to simplify some of my code, using the MSVC10 RC compiler.
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