I\'ve just seen this really nice talk Rock Hard: C++ Evolving by Boris Jabes. In the section of the talk concerning Higher-Order Generic Programming he says that the following is an example of a funct
I\'m attempting to solve a problem in which decltype will greatly simplify things, but I\'m running into an issue using decltype on *this and adding a const qualifier. The sample code below demonstrat
I was merily experimenting with the new trailing return types, where I hit a problem with this (simplified) code
Is auto x = initializer; equivalent 开发者_JAVA技巧to decltype(initializer) x = initializer; or decltype((initializer)) x = initializer;
I am making a templated class that is a wrapper around any iterator. I am making the operator* this way:
Say I have an objec开发者_开发知识库t of some of stl container classes obj. I can define other object of same type this way:
If we have the following: template <class T> struct B{ T data; } struct A{ int data_array[100]; } int main()
(Prompted by an answer.) Given N3290, §7.1.6.2p4, where the list items are unnumbered, but numbered here for our convenience:
Take a look at this: template<class T> struct X { private: T value_; public: X():value_(T()) {} X(T value):value_(value) {}
I very often see example of this form: template <typename T, typename U> auto add(T&& t, U&& u) -> decltype(std::forward<T>(t) + std::forward<U>(u))
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