How can I distinguish a variable as a compiler-constructed string? For example, while the rvalue \"Hello, World\" is of type const char*. const char* in itself does not mean that a pointer can\'t be
I wonder how the following can be done void f(string &&s) { std::string i(move(s)); /* other stuff */
It just occurred to me I noticed that std::string\'s substr operation could be much more efficient for rvalues when it could steal the allocated memory from *this.
I wa开发者_JAVA技巧nt to pass an rvalue through std::bind to a function that takes an rvalue reference in C++0x.I can\'t figure out how to do it.For example:
I\'m writing a app for both linux & windows, and noticed that the GCC build is producing a lot of useless calls to the copy constructor.
Consider the following: struct X { Y y_; X(const Y & y) :y_(y) {} X(Y && y) :y_(std::move(y)) {}
I ran into the problem that RValue does not allow implicit conversion. My questions is what implementation is better to \"bypass\" this limitation?
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I was wondering what use an rvalue reference member has class A { // ... // Is this one useful? F开发者_如何学Coo &&f;
Considering the high quality of today\'s compilers regarding return value optimization (both RVO and NRVO), I was wondering at what class complexity it\'s actually meaningful to start adding move cons
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