I found this code on a web site #include <iostream> using namespace std; struct Base { Base() { cout << \"Base\" << \" \"; }
Why can we have a virtual destructor but not virtual开发者_Go百科 constructor?The constructor chain can be determined at compile time, because you use new ClassName() always from the most specific cla
Why does calling the inherited IUnknown::Release() function on a IWICImagingFactory object in a destructor cause a \"CXX0030: Error: expression cannot be evaluated\" to be shown each entry in the obje
I have a specific case which is hard to isolate in a code snippet here but I can explain it... I have a class A : public B and A has a member pointer of some type foo * f. In the virtual destructor f
I\'ve just updated GCC from (I think) 4.5.6 to 4.6.1, under Windows, MinGW. Suddenly my NonInstantiable base class (from which you inherit with public virtual to prevent instantiation) refuses to work
This example below illustrates how to prevent derived class from being copied. It\'s based on a base class where both the copy constructor and copy assignment operator are declared private.
Why doesn\'t C++ make destructors virtual by default for classes that have at least one other virtual function?In this case adding a virtual destructor costs me nothing, and not having one i开发者_Sta
I tried the following code on gcc 4.4.5. If the member \'data\' is not present, the code executes fine, but in its presence, it crashes. It also doesn\'t crash when the derived class\' dtor is not vi
In this answer, Ryan directly calls the virtual destructor. I\'ve tested the code in VS2010, and it correctly calls all destructors (tested with logging statements). Is it actually valid to do so? Wha
Everyone says that a destructor should be virtual when at least one of class methods is virtual. My questions is, isn\'t it correct to say that a destructor should be virtual when using upcasting ?
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