I have a preprocessor macro defined in build settings FOO=BAR That value I want to massage into an Objective-C string l开发者_JS百科iteral that can be passed to a method.The following #define does
I\'ve come across this #define DsHook(a,b,c) if (!c##_) {INT_PTR* p=b+*(INT_PTR**)a;VirtualProtect(&c##_,4,PAGE_EXECUTE_READWRITE,&no); *(INT_PTR*)&c##_=*p;VirtualProtect(p,4,PAGE_EXECUTE
Note: This question has nothing to do with OpenCL per se... check the last paragraph for a succinct statement of my question. But to provide some background:
Suppose I have some macro #define NAME name, and I want to define some other macro which will expand to the quoted value. That is, as if I had also defined #define NAME_STR \"name\". Is there a neater
I’m trying to set scores in a cookie with a JSON string… var json = JSON.stringify({ s:{score:2000,name:\"Michael\"},
I came across this example of an asse开发者_如何学Gortion and was wondering what the # is for: #define ASSERT( x ) if ( !( x ) ) { \\
I am unable to understand how the preprocessor works and what does the ## stands for in this particular example
#definePATH\"yagh/headers/\" #defineFILNAME\"includefile\" #define CONCAT(a__, b__) CONCAT_DO(a__, b__)
#include <开发者_StackOverflow;stdio.h> #define f(a,b) a##b #define g(a)#a #define h(a) g(a) int main()
This question already has answers here: Closed 12 years ago. Possible Duplicate: How to single-quote an argument in a macro?
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