I\'m solving this dfs/bfs problem. I wrote both an iterative version and a recursive version of DFS.
I\'d like to use a stack and return a path, but I\'m thinking it\'s not possible. A node must be called directly by its parent so that it can receive the path behind it, whereas when this node is pu
According to the book (Intro to Algorithm), in dfs, edges are classified as 4 kinds: Tree Edge, if in edge (u,v), v is first discovered, then (u, v) is
I\'ve been trying this all week and cannot, for the life of me, figure it out. I know that I need to have a helper function that will recurse and return pathSoFar. I can\'t seem to get my head around
I have triangle collection that define mesh surface of my 3D shape, I would like to fix normal of each triangle to point outshape.
I have a tree (in the graph sense) representation of a tree (in the physical sense). The tree is represented as a BGL adjacency list where each vertex contains radius and position properties, i.e., my
Isn\'t it redundant to rescan n-1 levels of nodes f开发者_运维问答or each iteration?I quote from Artificial Intelligence: A Modern Approach:
Why are the running times of BFS and DFS O(V+E), especially when there is a node that has a directed edge to a node that can be reached from the vertex, like in this example in the f开发者_运维问答oll
Here\'s the situation: The application world consists of hundreds of thousands of states. Given a state, I can work out a set of 3 or 4 other reachable states. A simple recursion can build a tree
There is group of people [let\'s say 1874 of them], all representing different companies [lets say 236 of them] in the world. My task is to best identify what company each person works for. The trick
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