I wrote this little script to format a timedelta object according to my needs: def due_format(self): time_diff = abs((self.due - datetime.datetime.now()).total_seconds())
This question originated when I came upon (another thread) about Python\'s datetime and timedelta objects.
I have a date \"10/10/11(m-d-y)\" and I want to add 5 days to it using a Python script. Please consider a general solution that works on the month ends also.
I\'m writing a function that needs to parse string to a timedelta. The user must enter something like "32m" or "2h32m", or even "4:13" or "5hr34m56s"... Is ther
Python: How to get the sum of timed开发者_如何学编程elta? Eg. I just got a lot of timedelta object, and now I want the sum. That\'s it!To add timedeltas you can use the builtin operator +:
I\'m trying to divide one timedelta object with another to calculate a server uptime: >>> import datetime
I want to calculate the avarage timedelta between dates i开发者_StackOverflown a list. Although the following works well, I\'m wondering if there\'s a smarter way?
I\'m using Java\'s java.util.Date class in Scala and want开发者_如何学JAVA to compare a Date object and the current time. I know I can calculate the delta by using getTime():
I have a time out of Linux that is in hh:mm:sec, but the hh can be greater than 24 hours.So if the time is 1 day 12 hours, it would be 36:00:00.Is there a way to take this format and easily make a tim
As per the title, I\'m trying to parse an XML file containing an xs:duration data type. I\'d like to convert that into a Python timedelta object, which I can then use in further calculations.
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