Python 2.6.5: Divide timedelta with timedelta
I'm trying to divide one timedelta
object with another to calculate a server uptime:
>>> import datetime
>>开发者_高级运维;> installation_date=datetime.datetime(2010,8,01)
>>> down_time=datetime.timedelta(seconds=1400)
>>> server_life_period=datetime.datetime.now()-installation_date
>>> down_time_percentage=down_time/server_life_period
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for /: 'datetime.timedelta'
and 'datetime.timedelta'
I know this has been solved in Python 3.2, but is there a convenient way to handle it in prior versions of Python, apart from calculating the number of microseconds, seconds and days and dividing?
Thanks,
Adam
In Python ≥2.7, there is a .total_seconds()
method to compute the total seconds contained in the timedelta:
>>> down_time.total_seconds() / server_life_period.total_seconds()
0.0003779903727652387
Otherwise, there is no way but to compute the total microseconds (for versions < 2.7)
>>> def get_total_seconds(td): return (td.microseconds + (td.seconds + td.days * 24 * 3600) * 1e6) / 1e6
...
>>> get_total_seconds(down_time) / get_total_seconds(server_life_period)
0.0003779903727652387
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