I have a list of words and I need to generate all possible permutations of these, with one caveat. I currently use the following code:
Given a dictionary mapping variables to possible outcomes: { \'lblA\' : [False, True], \'lblB\' : [False, True], \'lblC\' : [0,1,2] }
I have a list of lists. Using itertools, I am basically doing for result in product([A,B],[C,D],[E,F,G]):
Given these 2开发者_JAVA技巧 lists L2 = [A,B,C,D,A,B] L3 = [3,2,1,2,2,1] I want to obtain L2_WANTED = [A,B,C,D]
For a small project I\'m working on I need to cycle through a list. For each element of this cycle I have to start another 开发者_JAVA百科cycle through the same list, with the former element as first
I have a list that is created within an itertools.groupby operation: def yield_unpacked_list(): for key, grp in itertools.groupby(something_to_groupby, key=lambda x: x[0]):
I am almost finished with a task someone gave me that at first involved easy use of the produ开发者_如何学编程ct() function from itertools.
To illustrate, I start with a list of 2-tuples: import itertools import operator raw = [(1, \"one\"), (2, \"two\"),
I don\'t need the laziness of itertools.groupby. I just want to group my list into a dict of lists as such:
I guess it\'s an academic question, but the second result does not make sense to me. Shouldn\'t it be as thoroughly empty as the first? What is the rationale for this behavior?
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