I need a function that functions in a similar manner as itertools.product, but without repeating items.
In Python, I am using list(itertools.permutations(\"0123456789\")), and I am receiving (I as expected) a list of tuples of singled character strings.
import itertools def _yield_sample(): it = iter(itertools.combinations(\'ABCD\', 2开发者_如何学Go))
So this is what im trying list(itertools.combinations_with_replacement(\'01\', 2)) but this is开发者_StackOverflow社区 generating [(\'0\', \'0\'), (\'0\', \'1\'), (\'1\', \'1\')]
How should argmax be implemented in Pyth开发者_JAVA技巧on?It should be as efficient as possible, so it should work with iterables.
My function creates a chain of generators: def bar(num): import itertools some_sequence = (x*1.5 for x in range(num))
I have code like this: #opened file f goto_line = num_lines #Total number of lines w开发者_运维技巧hile not found:
When is it b开发者_JS百科etter to use zip instead of itertools.izip?zip computes all the list at once, izip computes the elements only when requested.
HI, I\'m try to find a general expression to obtain exponents of a multivariate polynomial of order order and with n_variables, like the one presented in this reference in equation (3).
I use itertools.product to generate all possible variations of 4 elements of length 13. The 4 and 13 can be arbitrary, but as it is, I get 4^13 results, which is a lot. I need the result as a Numpy ar
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