F# Computation Expressions allow to hide the complexity of monadic syntax behind a thick layer of syntactic sugar. Is there something similar available in Scala?
Learning Haskell is killing me. If I am going to write a function that takes an array of arrays of order-able elements, and outputs the same thing, how do I do that?
In an attempt to learn Haskell, I have come across a situation in which I wish to do a fold over a list but my accumulator is a Maybe. The function I\'m folding with however takes in the \"extracted\"
map :: (a -> b) -> [a] -> [b]开发者_C百科 fmap :: Functor f => (a -> b) -> f a -> f b
Here\'s the code I\'m trying to understand (it\'s from http://apocalisp.wordpress.com/2010/10/17/scalaz-tutorial-enumeration-based-io-with-iteratees/):
ghci> :t (>>=) (>>=) :: Monad m => m a -> (a -> m b) -> m b How come the second argument is (a -> m b) instead of (m a -> m b) or even (a -> b)? What is it concep
Is there any way to take \"things\" out of a monad? I am developing a game, and I am now trying to understand about databases. I found happstack really nice, but I can\'t get the thing.
Consider the next example. I have a monad MyM that is just a StateT {-# LANGUAGE TypeFamilies #-} import Control.Monad.State
Perhaps I\'m going about this the wrong way, but I\'m using HXT to read in some vertex data that I\'d like to use in an array in HOp开发者_如何学编程enGL. Vertex arrays need to be a Ptr which is creat
I just reinvented some monad, but I\'m not sure which.It lets you model steps of a computation, so you can interleave the steps of numerous computations to find which one finishes first.
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