How to take out a value out of a monad in Haskell?
Is there any way to take "things" out of a monad?
I am developing a game, and I am now trying to understand about databases. I found happstack
really nice, but I can't get the thing.
For example, I have this function (hope you are familiar with happstack
)
getAllThings :: MonadIO m => m [Thing]
getAllThings = do
开发者_JS百科 elems <- query GetThings
return elems
So I get m [Things]
, but I can't use this in my model! For instance
doSomeThingWithThings :: [Thing] -> Something
I googled this and I found nothing.
You are not supposed to exit IO monad this way (except unsafePerformIO
function), but you can still use your function inside it:
process :: MonadIO m => m ()
process = do
elems <- getAllThings
let smth = doSomeThingWithThings elems
-- ...
After elems <- query GetThings
the elems is [Thing]
so <-
inside do is about getting things out of monad (called bind operation). The last statement return
put things inside a monad. So either you can call you other function after getting elems and before return
or where ever you are calling getAllThings
you can use extract the value using <-
from the monad and pass it to your function
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