What I\'ve written is: typedef enum _MyStatus { MY_STATUS_OK = 0, MY_STATUS_GENERAL_ERROR = -1, } MyStatus;
let\'s say I have the following code in A.cpp file: template <typename T> class A{ typedef T myType;
I\'m trying to typedef a struct which contains a pointer to another of the same type. Thats what I thought would be the best version:
I came 开发者_如何学Cacross a new use of the keyword typedef in C++. What does this typedef statement mean ?
I\'m currently stuck with a legacy code using multiple dimensions arrays : #define B 25 int Table[A][B][C][D][E][F];
After getting an answer to this question I discovered there are two valid ways to typedef a function pointer.
So after searching a lot for an answer to my question, I finally gave up on my Google skills. I have an base class Base, and a derived class Derived. I want to override a type in the Base class with
I have two functions in a class (please comment on the issue and not the coding style): template <typename T>
In Objective C, when you define an enum, all of the enum values are visible everywhere and clog the global namespace.
When I was compiling a C++ program using icc 11, it gave this warning: warning #21: type qualifiers are meaningless in this declaration
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