I am trying to declare a size of a char array and I need to use the value of the variable that is declared as a size_t to declare that size.Is there anyway I can cast the size_t variable to an int so开
I have the code: unsigned int length = strlen(somestring); I\'m compiling with the warning level on 4, and it\'s telling me that \"conversion from size_t to unsigned int, possible l开发者_如何学JAV
Is size_t开发者_如何学C only in C++ standard or C standard as well? I cannot find a C header in the \"/usr/include\" tree that defines size_t.
I want to print out a variable of type size_t in C but it appears that size_t i开发者_高级运维s aliased to different variable types on different architectures. For example, on one machine (64-bit) the
GCC 4.4.1, C99 I am using size_t, and size_t is an unsigned int. However, that depends if you are running 32 bit or 64 bit.
I have some C++ code that prints a size_t: size_t a; printf(\"%lu\", a); I\'d like this to compile 开发者_运维百科without warnings on both 32- and 64-bit architectures.
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