This question already has an answer here: Closed 10 years ago. Possible Duplicate: 开发者_StackOverflowTest for NA and select values based on result
Is there a single function in R that determines if a value is NA,开发者_C百科 NaN, Inf, -Inf, or otherwise not a well-formed number?You want is.finite
My question is rather simple. What I want is if A[i]!=NA, then C[i]=A[i], if A[i]=NA, then C[i]=B[i], however, I always get some error messages. Can somebody help me out?
I have huge matrix with a lot of missing values. I want to get the correlation between variables. 1. Is the solution
I have a question similar to this one, but my dataset is a bit bigger: 50 columns with 开发者_运维百科1 column as UID and other columns carrying either TRUE or NA, I want to change all the NA to FALSE
What is the fastest way to detect if a vector has at least 1 NA in R?I\'ve been using: sum( is.na( data开发者_运维技巧 ) ) > 0
Quic开发者_C百科k question. I read my csv file into the variable data. It has a column label var, which has numerical values.
Say I have the following R data.frame ZZZ: ( ZZZ <- structure(list(n = c(1, 2, NA), m = c(6, NA, NA), o = c(7, 8,
近日，由天艺九鸣New Actor Project推出的新人演员刘亦城、孙胤嘉正式亮相，并曝光西装写真。天艺New Actor Project，简称天艺NAProject，是随着天艺铭禾在行业发展与艺人品牌管理经验逐开发者_JS百科渐成熟，于成立
I 开发者_JAVA百科have a data frame containing (in random places) a character value (say \"foo\") that I want to replace with a NA.
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