For example: struct Foo { int bar; int (*baz)(int); }; int testFunc(int x) { return x; } Foo list[] = { { 0, &testFunc },
What would typedef int (&rifii) (int, int) be used for? What is the typedef before this \"statement\" do?
If I compile the code below, I get an \"Error C2064: term does not evaluate to a function taking 2 arguments\"
My situation is the following: I am writing a toolbox that generates two libraries. The first (A) has all the functions and data-types and can be used in a pure C++ application; the second (B) is an
Why does the following print 1. I was expecting it to print the address of the function pointer. #include <stdio.h>
I want to stop the warning server.cpp:823: warning: converting from \'void* (ClientHandler::)()\' to \'void ()(void)\'
I\'m been grinding my head against an idea that is simple enough in my head, but I can\'t figure out how to implement in C++.
If you have a struct like this one struct A { void func(); }; and a reference like this one A& a; you can 开发者_如何学Cget a pointer to its func method like this:
Greating everybody! I have a function-pointer method int Myclass::*myMethod(char* a,char* b){ //some code
I need to implement callback function in Java using “interface”开发者_如何学编程. I have wrote the application part as MyJavaFunction(int size, m_GetSizeInterface);
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