void (*func)(int(*[ ])()); 开发者_开发技巧The general procedure for reading hairy declarators is to find the leftmost identifier and work your way out, remembering that [] and () bind before * (i.e.,
I want to pass an array of arbitrary struct pointers and a comparison function to a generic sorting algorithm. Is this possible in C?
Why does this code int (*g)(int); int (*h)(char); h开发者_JAVA技巧 = g; In C, give me such warning when compiling:
I have always been a bit stumped when I read other peoples\' code which had typedefs for pointers to functions with arguments. I recall that it took me a while to get around to such a definition while
I\'m using reflection to examine the following method declaration and am wondering if it is poss开发者_如何转开发ible to determine that the method\'s sole parameter is a function pointer.
I have some binary data which contains a bunch of functions and want to call one of it. I know the signature of these functions along with the offset relative to t开发者_如何学Pythonhe start of the fi
Here is my Code: I want to use a class inside my custom MyStateMachine. I do not want to inherit de StateMachine class as I just want to use it with its functions. The MyStateMachine class is only to
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