Is there a bui开发者_如何学Pythonltin function to get url like this: ../images.html given a base url like this: http://www.example.com/faq/index.html and a target url such as http://www.example.com/im
I am currently working on a project that involves splitting a url. I have used the urlparse module to break up the url, so now I am working with just th开发者_开发技巧e path segment.
I\'m trying to write a script to test for the ex开发者_StackOverflowistence of a web page, would be nice if it would check without downloading the whole page.
This question already has answers here: How can I prepend http to a url if it doesn't begin with http?
warning message: File \"procesador.py\", line 10, in <module> from model import * File \"/Users/juque/Proyectos/est/patan/_patan/model.py\", line 14, in <module>
Which URL parsing function pair should I be using and why? urlparse and 开发者_运维技巧urlunparse, or
I know that with urllib you can parse a string and check if it\'s a valid URL. But how would one go about checking if a sentence contains a URL within it, and then ext开发者_如何学Pythonract that URL.
I\'m doing this: urlparse.urljoin(\'http://example.com/mypage\', \'?name=joe\') And I get this: \'http://example.com/?name=joe\'
I\'m making an app that parses html and gets images from it. Parsi开发者_运维技巧ng is easy using Beautiful Soup and downloading of the html and the images works too with urllib2.
I\'m writing something to \'clean\' a U开发者_如何学JAVARL. In this case all I\'m trying to do is return a faked scheme as urlopen won\'t work without one. However, if I test this with www.python.org