Splitting a url into a list in python

I am currently working on a project that involves splitting a url. I have used the urlparse module to break up the url, so now I am working with just th开发者_开发技巧e path segment.

The problem is that when I try to split() the string based on the delimiter "/" to separate the directories, I end up with empty strings in my list.

For example, when I do the following:

import urlparse
url = "http://example/url/being/used/to/show/problem"
parsed = urlparse.urlparse(url)
path = parsed[2] #this is the path element

pathlist = path.split("/")

I get the list:

['', 'url', 'being', 'used', 'to', 'show', 'problem']

I do not want these empty strings. I realize that I can remove them by making a new list without them, but that seems sloppy. Is there a better way to remove the empty strings and slashes?

I do not want these empty strings. I realize that I can remove them by making a new list without them, but that seems sloppy. Is there a better way to remove the empty strings and slashes?

What? There's only one empty string and it's always first, by definition.

pathlist = path.split("/")[1:] 

Is pretty common.

A trailing slash can mean an "empty" filename. In which case, a default name may be implied (index.html, for example)

It may be meaningful.

"http://example/url/being/used/to/show/problem"

The filename is "problem"

"http://example/url/being/used/to/show/problem/"

The directory is "problem" and a default filename is implied by the empty string.

I am not familiar with urllib and its output for path but think that one way to form new list you can use list comprehension the following way:

[x for x in path.split("/") if x]

Or something like this if only leading '/':

path.lstrip('/').split("/")

Else if trailing too:

path.strip('/').split("/")

And at least if your string in path always starting from single '/' than the easiest way is:

path[1:].split('/')

pathlist = paths.strip('/').split("/")

remove the empty items?

pathlist.remove('')

I added this as a comment to a comment, so just in case: Couldn't you use a list comprehension to exclude the empty elements returned from the split, i.e.

path_list = [(p) for p in path.split('/') if len(p)]