MemoryStream from bytes array with different types of data
I want to create a memory stream which contains int32, int16, single values. Using binarywriter is useless so i tried to make bytes array. Because values are in different types, I don't know how to do it properly. So I try do like that:
byte[] tab = new开发者_运维知识库 byte[]{2,0,0,0,3,0,3,0}
- 2 is int32 (four bytes), another two 3 are int16 (two bytes)
that works fine, but when i want to add some single values, it generates errors. I cant do like that :
byte[] tab = new byte[]{2,0,0,0,3,0,3,0,4.4f,5.6f}
I must have stream in proper format, cause that stream will be read in this method :
short[] rawData;
float[] modulusData;
public void rawData(Stream s)
{
BinaryReader br = new BinaryReader(s);
int dataCount = br.ReadInt32();
if (dataCount > 0)
{
rawData = new short[dataCount];
for (int i = 0; i < dataCount; i++)
rawData[i] = br.ReadInt16();
}
else
rawData = new short[0];
dataCount = br.ReadInt32();
if (dataCount > 0)
{
modulusData = new float[dataCount];
for (int i = 0; i < dataCount; i++)
modulusData[i] = br.ReadSingle();
}
else
modulusData = new float[0];
}
Anybody has idea how to do that ??
Contrary to your original statement, BinaryWriter
is exactly what you want. That's what it's designed for. In particular, it's exactly appropriate if you're going to use BinaryReader
later.
You haven't stated why you don't want to use it, but it really is what you should use:
using (MemoryStream stream = new MemoryStream())
{
using (BinaryWriter writer = new BinaryWriter(stream))
{
writer.Write(2);
writer.Write((short) 3);
writer.Write((short) 3);
writer.Write(4.4f);
writer.Write(5.6f);
}
byte[] bytes = stream.ToArray();
}
This produces a byte array with the following data:
[Int32 ] [Int16] [Int16] [Single ] [Single ]
02 00 00 00 03 00 03 00 CD CC 8C 40 33 33 B3 40
One point to note - your writing description writes these values:
- Int32
- Int16
- Int16
- Single
- Single
... but your reading code will read:
- Int32 (value 2)
- Int16
- Int16
- Int32 (this wasn't written - so you're reading data from the first Single!)
- ???
In other words, if your previous attempts with BinaryWriter
were failing because they looked like my initial code, it's because you forgot a
writer.Write(2);
after writing the Int16 values, to say how many Single values were present.
Note that if you don't need the values as a byte array, you don't need to call ToArray
- just return the stream (without disposing of it). However, you'll want to "rewind" it before reading it. For example:
public Stream GetData()
{
MemoryStream stream = new MemoryStream();
BinaryWriter writer = new BinaryWriter(stream); // Don't close at the end!
writer.Write(2);
writer.Write((short) 3);
writer.Write((short) 3);
writer.Write(2); // Extra count for the Single values
writer.Write(4.4f);
writer.Write(5.6f);
writer.Flush(); // May not be required...
stream.Position = 0; // Rewind so stream can be read again
return stream;
}
A BinaryWriter isn't useless at all. Just create a memorystream and write to it:
MemoryStream m = new MemoryStream();
using (BinaryWriter writer = new BinaryWriter(m)) {
writer.Write(2); // count
writer.Write((short)3);
writer.Write((short)3);
writer.Write(2); // count
writer.Write(4.4f);
writer.Write(5.6f);
}
byte[] tab = m.ToArray();
Note that I added a count for the float values also. It's not in your example data, but the method that reads the data needs it.
I verified that the data can be read properly. I used your reader code, and wrote out the result:
Console.WriteLine(rawData.Length);
foreach (short x in rawData) Console.WriteLine(x);
Console.WriteLine(modulusData.Length);
foreach (float f in modulusData) Console.WriteLine(f);
Output:
2
3
3
2
4,4
5,6
Constructing a byte array like this doesn't work, because the Int32
and Int16
will be implicitly converted to byte
, which doesn't happen for the floating point numbers, hence your compiler error.
The best way is to write to the stream in the same manner you read from it using, BinaryWriter
(See the other answers)
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