1 line. Where to place ID in the link

I have created a separate posting from the large one of before because I think to have isolated the cause of the ID value not getting passed.

I have this link, but there is something not fully correct and no value is sent.

$sOutput .= '"<a href=\"#' ."id=" .addslashes($aRow['id_cruise']) .'\" class=\"flip\">'.addslashes($aRow['from_country']).'</a>",';

That above is the line of interest.

And for curiosity, this is the snippet which receives the value

<script type="text/javascript"> 
$(document).ready(function(){
$('a.flip').live('click',function(){
    $(".panel").slideToggle("slow");
    $('#reviews').load('SendIdToDatabase.php', {idCruise: this.id});
     });
});

</script>

So, the whole scenario is:

A table, rows and links on a column in the rows.

When you click on the link, 2 things should happen.

a) A slide panel is opened

b) and the value is passed to a DIV inside that panel (div which loads the result of a php query which received that ID value)

but like I said, it is expected that only the Link needs to be tweaked

thanks a million

Alvaro

UPDATE

Well, 2 links have been proposed. None 开发者_运维技巧of them works.

This link allows the Slide Panel to open but it does not populate the div inside it

$sOutput .= '"<a href=\"#\"' .' id=\"' .addslashes($aRow['id_cruise']) .'\" class=\"flip\">'.addslashes($aRow['from_country']).'</a>",';

And this link seems to do just the opposite. The slide wont open but the div seems to be loading info but I cant see it because the slide, like I said, doesnt open

$sOutput .= '"<a href=\"?id=' .addslashes($aRow['id_cruise']) .'\" id=\"' .addslashes($aRow['id_cruise']) .'\" class=\"flip\">'.addslashes($aRow['from_country']).'</a>",'; 

So, the goal is to get 1 Line that can make both things happening. Open the slide, and populate the div. Of course, using the JQUERY snippet shown

Alvaro, It seems to me your link building code is incorrect, ie

$sOutput .= '"<a href=\"#' ."id=" .addslashes($aRow['id_cruise']) .'\" class=\"flip\">'.addslashes($aRow['from_country']).'</a>",';

would echo to the screen

<a href="#id=id_cruise" class="flip">from_country</a>

Your HTML code is wrong, in that you haven't closed off the href and your browser thinks the href is href="#id=id_cruise" instead of your what I think you are trying to do

 $sOutput .= '"<a href=\"#\"' .' id=\"' .addslashes($aRow['id_cruise']) .'\" class=\"flip\">'.addslashes($aRow['from_country']).'</a>",';

which should echo out the correctly formed HTML like this:

<a href="#" id="id_cruise" class="flip">from_country</a>

Now your href & id attributes are correctly formed, jQuery should be able to play nicely.

Cheers, J.