Parsing a string which represents a list of tuples [duplicate]

This question already has answers here: How to convert string representation of list to a list (19 answers) Closed 2 months ago.

I have strings which look like this one:

"(8, 12.25), (13, 15), (16.75, 18.5)"

and I would like to convert each of them into a python data structure. Preferably a list (or tuple) of tuples containing a pair of float values.

I could do that with eval("(8, 12.25), (13, 15), (16.75, 18.5)") which gives me a t开发者_StackOverflow社区uple of tuples, but I don't think naively evaluating external information would be a wise decision.

So I wondered what an elegant pythonic solution might look like.

---

>>> import ast
>>> print ast.literal_eval("(8, 12.25), (13, 15), (16.75, 18.5)")
((8, 12.25), (13, 15), (16.75, 18.5))

---

def parse(s):
    tuples = s.split('), ')
    out = []
    for x in tuples:
        a,b = x.strip('()').split(', ')
        out.append((float(a),float(b)))
    return out

this should do the job.

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I've used safe_eval for jobs like this in the past.

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If you're working with a CSV file, and you want more than the "naive" solution which doesn't handle any errors, you're probably best off using the Python's CSV module.

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Download PyParsing.

I've worked with it before. You can get some pretty robust parsing behavior out of it, and I think it provides builtins that will handle your entire parsing needs with this sort of thing. Look up commaSeparatedList and nestedExpr.

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what's wrong with doing it systematically ? split on ")", then go through the list, remove all "(".

>>> s="(8, 12.25), (13, 15), (16.75, 18.5)"
>>> [ i.replace("(","") for i in s.split(")") ]
['8, 12.25', ', 13, 15', ', 16.75, 18.5', '']
>>> b = [ i.replace("(","") for i in s.split(")") ]
>>> for i in b:
...  print i.strip(", ").replace(" ","").split(",")
...
['8', '12.25']
['13', '15']
['16.75', '18.5']
['']

Now you can bring each element into your data structure.