#include <type_traits> template<class开发者_StackOverflow中文版 T> typename std::remove_reference<T>::type&& move(T&& v)
How can I distinguish a variable as a compiler-constructed string? For example, while the rvalue \"Hello, World\" is of type const char*. const char* in itself does not mean that a pointer can\'t be
Being not declared constexpr, std::forward will discard constexpr-ness for any function it forwards arguments to. Why is std::forward not declared constexpr itself so it can preserve constexpr-ness?
As far as I understand one of the purposes of addingmove semantics is to optimize code by calling special constructor for copying \"temporary\" objects. For example, in this answer we see that it can
After finding the answer to How to return an fstream (C++0x), I was now wondering if t开发者_运维百科here is a current c++0x library that implements move (or even swap) for fstreams (as gcc (27.9) doe
I think I\'ll get right into it and start with the code: #include <iostream> #include <fstream>
I\'m a simple programmer.My class members variables most often consists of POD-types and STL-containers. Because of this I seldom have to write assignment operators or copy constructors, as these are
Consider the following: struct X { Y y_; X(const Y & y) :y_(y) {} X(Y && y) :y_(std::move(y)) {}
In the forthcoming C++0x standard, what happens开发者_Python百科 when an exception is thrown within/during the move constructor?
Considering the high quality of today\'s compilers regarding return value optimization (both RVO and NRVO), I was wondering at what class complexity it\'s actually meaningful to start adding move cons