I was so happy when I discovered IsLittleEndian field in BitConverter. I thought of course it should be the开发者_高级运维re and I should be able to specify whatever endian I like. Well, my happiness
Suppose there is only one single double value written into a file in binary format. How can I read that value using C# or Java?
I\'m trying to send a 28 character string to a remote ip address and port. I\'ve done this successfully in vb.net using the following code snippets:
Just wondering if someone could explain why the two following lines of code return \"different\" results? What causes the reversed values? Is this something to do with endianness?
The documentation of Bit开发者_如何学PythonConverter.IsLittleEndian says: Indicates the byte order (\"endianness\") in which data is stored in this computer architecture.
I have this code for converting a byte[] to float[]. public float[] ConvertByteToFloat(byte[] array) { float[] floatArr = new float[array.Length / sizeof(float)];
In our application, we have a very large byte-array and we have to convert these bytes into different types. Currently, we use BitConverter.ToXXXX() for this purpose. Our heavy hitters are, ToInt16 an
I have a need to convert an Int32 value to a 3-byte (24-bit) integer. Endianness remains the same (little), but I cannot figure out how to move the sign appropriately. The values are alr开发者_如何学C
How would I convert this into 开发者_JAVA百科a loop and not to use the pointer. byte[] InputBuffer = new byte[8];
I\'ve got a problem here that\'s probably something that I\'m just overlooking, but I can\'t understand why it\'s happening...
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