I have a simple line of text which might include numbers like \"12.3\" or \"1983\" or \"5/8\". Whenever any number appears, I just need to replace with a fixed character, say the digit \"8\".
I am using InputFilter class to make a masked EditText supporting digit grouping. For example when the user inserts\" 12345\" I want to show \"12,345\" in EditText. How can I implement it?
Hi I am wondering is there anyway to make a single digit number ie:1 become 01 This is the code I using at the moment but all the single digits are only coming out as single digits
I\'m trying to use long for 12 digit number but it\'s saying \"integer constant is too large for \"long\" type\", and I tried it with C++ and Processing (similar to Java).What\'s happening and what sh
I have a number like 0.5, I would like to keep two digits 开发者_如何学JAVAin order to make the number 0.50. While the last digit is zero, so it always cannot appear.
This is my code, and it keeps repeating until :eq(15). I\'m new to jQuery and JavaScript in general and I doubt that I\'m doing this correctly. Can anyone help me with cleaning this code up into a loo
Hi StackOverflow experts, I\'ve darag n\' droped a field into the iReport. This field holds the java.lang.BigDecimal expression class data returned by Query of the Report. In the MSSQL DataBase table
How can I leave only words in uppercase, digits, s开发者_如何学Cpecial characters, or words where the first letter in uppercase, but it contains no more than 3 characters, with preg_replace.
I need the regular expression for multiplying the digits in the 开发者_运维问答filename by 2 and subtracting 1.
I am trying to use a Dojo Digit Theme in my Rails 3 Form. Below is my attempt to incorporate Dojo in the Devise views/sessions/new.html.erb file. The Login and Password textboxes are displayed using t
加载中,请稍侯......