this is the actual query Select members.member_Id, membertomships.memberToMship_DueDay, sum(memberToMship_Char开发者_开发知识库gePerPeriod)-sum(memberAccTran_Value) as StillDue
I have set up a price comparison tool that crawl开发者_如何学JAVAs websites and then detects price changes. I have a table that contains the price, the items id and the scan id. I have another table w
Here\'s the initial query: SELECT COUNT(column) FROM table GROUP BY column; This gives me something like the following:
I have the following tables set up: Articles: ID | TITLE | CONTENT | USER | NUM_COMMENTS COMMENTS ID | ARTICLE_ID | TEXT
Is this possible? I have 2 tables, Customers and Orders. Now I want to fill a column in Customers with all order id\'s of that customer (comma separated).
I keep getting this stateme开发者_StackOverflow社区nt \"Invalid use of group function\" for this query
select max( sum(duration) ),cd from rent group by cd;开发者_运维问答 . ERROR 1111 (HY000): Invalid use of group function From documentation - group (aggregate) functions that operate on sets of va
how can I group concat? here is my query select t.date, group_concat(count(*)) from table1 t group by t.date
I have a simple MySQL select statement: SELECT COUNT(*) AS COUNT FROM MY_TABLE WHERE TIME_STAMP > ?
I am trying to calculate com开发者_高级运维missions payable to clients at the beginning of every month (providing their commission is more then £25).
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