I love the ease of django\'s pagination system, but is there anyway to tweak it where it\'s paginating by item id instead of page number? Because I am ordering in descending order, if there is an upda
I am using django generic views, how do I get access to the request in my template. URLs: file_objects = {
I\'m filtering out results from my page_obj in a generic view to only show entries published in the same language as the languge currently set by django-cms (http://www.django-cms.org/en/documentation
from django.conf.urls.defaults import * from django.conf import settings from Website.Blog.models import Post
I\'m trying to display the latest 5 posts using a generic view like this: urlpatterns = patterns(\'\',
I\'m currently working with django generic views and I have a problem I can\'t figure out. When using delete_object I get a TypeError exception:
I made in my web a menu using generic_view - simple \'django.views.generic.list_detail.object_list\' in urls.py file.
I have 3 models with various fields in each.For 2 of the models, I\'m fine with using a generic form (through Django\'s create_object) to request data.I wrote a function that accepts the model name an
Is there an easy way to get the URL to a Django date-based generic view (specifically object_detail) from a template?
This seems like it should be obvious, but the solution is eluding me. Normally I would just write a simple view function which would populate an appropriate form and pass it along to the view, but the
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