The following code confused me a bit: char * strcpy(char * p, const char * q) { while (*p++=*q++); //return
I\'m using the book \"Programming Principles and Practice using C++\" to learn programming and one of the exercises is looping through the characters a-z using a while-loop.
I know that the postfix versions of the increment/decrement operators will generally be optimised by the compiler for built-in types (i.e. no copy will be made), but is this the case for iterators?
This question already has answers here: How do the post increment (i++) and pre increment (++i) operators work in Java?
I understand this is part of the basic stuff, but i am stuck :-( Can someone please help me? Program 1:
This question already has answers here: Closed 11 years ago. Possible Duplicate: Is it allowed to name the parameter in postfix operator ++?
I admit that I asked a question about why Closure Compiler does not shorten certain code which looks shortenable at first sight a few days ago already, but that reason is not applicable in this case a
This question already has answers here: Closed 11 years ago. Possible Duplicate: Undefined Behavior and Sequence Points
From the program below or here, why does the last call to System.out.println(i) print the value 7? class PrePostDemo {
I\'m r开发者_如何学运维eading bytes from a buffer. But sometimes what I\'m reading is a word or longer.
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