I would like to know how to get order of optional argument passed from commandline to argparse I have image processing class which is able to apply different actions to image - like rotate, crop, res
I found the very useful syntax parser.add_argument(\'-i\', \'--input-file\', type=argparse.FileType(\'r\'), default=\'-\')
I\'m trying to make argparse ignore the fact that two normally required positional arguments shouldn\'t be evaluated when an optional argument (-l) is specified.
The documentation for the argparse python module, while excellent I\'m sure, is too much for my tiny beginner brai开发者_如何学Pythonn to grasp right now. I don\'t need to do math on the command line
I am using python argparse with the following argument definition: parser.add_argument(\'path\', nargs=1, help=\'File path to process\')
I\'m writing a relatively simple Python script which supports a couple of different commands. The different commands support different options and I want to be able to pass the options parsed by argpa
I am trying to use ArgumentParser.set_defaults from argparse. I want a keyworded tuple like this: parser.set_defaults(bar=42, baz=\'badger\')
I\'d like to use my program this way: pythonScript -f filename But if I forgot -f, I still want to get the filename.
Some questions that I couldn\'t figure out from reading the docs and some other questions. 1: I was stumped by \"how do I actually retrieve the arguments\" so I looked around and someone suggested to
I\'ve been using argparse for a Python program that can -process, -upload or both: parser = argparse.ArgumentParser(description=\'Log archiver arguments.\')
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