Suppose that we have the following bit of code: #include <pthread.h> #include <stdio.h> #include <stdlib.h>
Is there any good reason for operator = not being a sequence point? 开发者_开发百科Both in C and C++.
Is there a guaranteed sequence of execution of the following java code: int开发者_StackOverflow i = getA() + getB();
Can compiler reorder variable setting and throw() op in C++? Or, does standa开发者_JAVA百科rd C++ 14882-1998 allows or prohibit compiler of this transform?
What are "sequence points"? What is the relation between undefined behaviour and sequence points?
Why does the following gi开发者_开发技巧ven expression invoke undefined behavior? int i = 5; i = (i,i++,i) + 1
Lately, I have seen a lot of questions being asked about output for some crazy yet syntactically allowed code statements like like i = ++i + 1 and i=(i,i++,i)+1;.
Sorry for opening this topic again, but thinking about this topic itself has started giving me an Undefined Behavior. Want to move into the zone of well-defined behavior.
void mai开发者_运维知识库n(void) { int x,y,z; x=y=z=1; z = x && y && ++z;//is this fine?
#include<stdio.h> int main() { int i=7,j; j=(i++,++i,j*i); return 0; 开发者_StackOverflow中文版}
加载中,请稍侯......