According to C++ Standard (5/5) dividing by zero is undefined behavior. Now consider this code (lots of useless statements are there to prevent the compiler from optimizing code out):
If I divi开发者_如何转开发de by 0, I get either a ZeroDivisionError, Infinity or NaN depending on what is divided.
In my example X is already long and Y is a long also. I am not casting at then. I really just want to divide by a number that is cubed. (using native libraries)
I have an expr开发者_JAVA技巧ession that includes divisions, for which some of the denominators are sometimes zero. However, in those cases I would like that division to result in 1, instead of throwi
I had already searched through开发者_如何学Go different questions on this topic but not get a clear idea.
Why is X % 0开发者_JAVA技巧 an invalid expression? I always thought X % 0 should equal X. Since you can\'t divide by zero, shouldn\'t the answer naturally be the remainder, X (everything left over)?T
SELECT((CASE WHEN (qid2.AgeBelow_16 - qid1.AgeBelow_16)= 0 THEN 1 ELSE (qid2.AgeBelow_16- qid1.AgeBelow_16) END )/ (CASE WHEN [qid1].AgeBelow_16= 0 THEN 1 ELSE [qid1].AgeBelow_16END))*100 AS AgeBelow_
I currently have some code where I have to normalize a vector of doubles (divide each element by the sum). When debugging, I see sometimes that the elements in the vector are all 0.0. If I then take t
开发者_如何转开发 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references,or expertise, but this question will likely
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical andcannot be reasonably answered in its current form. For help clari
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