i did an overloading of the + operator but now i wanna do overloading of == operator of 2 lengths (may or may not be the same length) and return the respective results. How do i do it? Do i need to us
I am getting a unusual error: error: expected unqualified-id before ‘&’ token Source code: // Overloading the c++ array subscript operator [ ]
I dont understand, why is the aaa operator called in the 2nd last line? #include <iostream> class MyClass
I am completely perplexed. I have an object containing a global \"hashed\" array of numbers (in objectA) that is referred in a loop that combines the numbers into a new series (in objectB).
getting this error: C:\\CodeBlocks\\kool\\praks3\\vector.h|62|error: passing \'const Vector<2u>\' as \'this\' argument of \'std::string Vector::toString() [with short unsigned int n = 2u]\' discar
This question al开发者_如何学运维ready has answers here: Is there a built in function for string natural sort?
I am using a library that defines output stream operators (operator<<) in the global namespace. In my own namespace, I was always declaring such operators in the global namespace, and never had
I spent several hours today hunting for a b开发者_C百科ug until I found something I don\'t understand.
I have the following code. The code works fine without the operator + part. It gives me error: no match for ‘operator=’ in ‘final[i][j] = (((matrix*)this)->matrix::mat[i][j] + matr->matrix::mat[
I started out programming with C# a few days ago. Now an confusing error arised when playing around with operator overloading.
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