Does anybody know if there is a trick to toggle all the cout << function开发者_如何学Cs to not print out visible output? I am trying to hack together some code written by me and some other peopl
I\'m working on a project that makes me store an array of objects whose constructor is Item(char* item, int itemType){
First, this is homework, so I can not dynamically allocate memory for an array of any size, and I can not use a vector.
I have something like: int8_t value; value = -27; std::cout << value << std::endl; When I run my program I get a wrong random value of <E5> outputted to the screen, but when I ru
I need my program to behave differently, depending on whether the output is to a terminal or to a file. How can I find this out from within C++?
I have a small function, which is supposed to make a prediction based on a machine learning algorithm. The function wasn\'t working, so I put a print statement in to check on the val开发者_JAVA百科ue,
I saw this question already on this forum but I do not know why the proposed answer does not work in my case. So I try to ask for other slution.
I noticed a weird problem while using wcout in a console application. Aft开发者_如何学运维er calling a certain function, the rest of the wcout calls did not work at all. i.e. the output statements di
$ uname -a Darwin Wheelie-Cyberman 10.8.0 Darwin Kernel Version 10.8.0: Tue Jun7 16:33:36 PDT 2011; root:xnu-1504.15.3~1/RELEASE_I386 i386
I have a question regarding C++. This is my current function: string clarifyWord(string str) { //Remove all spaces before string
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