The following code is copied almost verbatim from section 9.1.1 of the book C++ Template Metaprogramming: Concepts, Tools, and Techniques from Boost and Beyond by David Abrahams & Aleksey Gurtovoy
This question already has answers here: Can I obtain C++ type names in a constexpr way? (3 answers) Closed 1 year ago.
I hav开发者_运维知识库e the following “main” template: template < template <typename> class S
I have a set of classes that have the following structure: class U { public: explicit U(int) { ... } U() {...}
Is it possible to address the following scenario of choosing the argument at runtime开发者_如何学C with mpl?
I use a class A from a library and want to add some functionality to it via an own class B. The user of c开发者_如何转开发lass B should derive from it as if he would derive from class A.
#include <iostream> #include <boost/fusion/mpl.hpp> #include <boost/fusion/include/mpl.hpp>
I\'m new to boost::fusion and boost::mpl libraries. Could anyone please tell me the main difference between these two libraries?
I wish to inherit from a set of classes contained in a boost mpl::vector.Is this possible? Specifically, I wish to extend test for arbitrary many template parameters, passed as a mpl::vector.
The following code does not compile on g++ (GCC) 4.6.0 20110603 (prerelease) with -std=c++0x and Boost 1.46.1.
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