C++ automagically calls destructors of all local variables in the block in reverse order regardless of whether the block is exited normall开发者_开发百科y (control falls through) or an exception is th
Doe开发者_JS百科s the destructor deallocate memory assigned to the object which it belongs to or is it just called so that it can perform some last minute housekeeping before the object is deallocated
We have a large body of native C++ code, compliled into DLLs. Then we have a couple of dlls containing C++/CLI proxy code to wrap the C++ interfaces.
Does a d开发者_如何学编程estructor get called if the app crashes? If it\'s an unhandled exception I\'m guessing it does, but what about more serious errors, or something like a user killing the applic
Consider this classic example used to explain what not to do with forward declarations: //in Handle.h file
When creating a new instance of a MyClass as an argument to a function like so: class MyClass { MyClass(int a);
After compiling of c++ file (with global static object) I get in 开发者_JS百科nm output this function:
Consider the following code: std::string my_error_string = \"Some error message\"; // ... throw std::runtime_error(std::string(\"Error: \") + my_error_string);
I would like my class to have a static pointer to a dynamically allocated region of memory.I understand how to initialize it - in my case I will initialize it when the first object needs it.However, I
class MyDestructableClass { function __construct() { print \"\\nIn constructor\\n\"; $this->name = \"MyDestructableClass\";
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