Destruction of string temporaries in thrown exceptions

Consider the following code:

std::string my_error_string = "Some error message";

// ...

throw std::runtime_error(std::string("Error: ") + my_error_string);

The string passed to runtime_error is a temporary returned by string's operator+. Suppose this exception is handled something like:

catch (const std::runtime_error& e)
{
    std::cout << e.what() << std::endl;
}

When is the temporary returned by string's operator+ destroyed? Does the language sp开发者_JAVA技巧ec have anything to say about this? Also, suppose runtime_error took a const char* argument and was thrown like this:

// Suppose runtime_error has the constructor runtime_error(const char* message)
throw std::runtime_error((std::string("Error: ") + my_error_string).c_str());

Now when is the temporary string returned by operator+ destroyed? Would it be destroyed before the catch block tries to print it, and is this why runtime_error accepts a std::string and not a const char*?

runtime_error is a class which contains a string. That string will be managed for you by the normal C++ construction and destruction mechanisms. If it contained a char *, then that would have to be explicitly managed, but you would still not have to do anything as a user of runtime_error.

Despite what you may read elsewhere on the internet, C++ is designed to almost always do "the reasonable thing" - you actually have to try fairly hard to break this reasonable behaviour, though of course it is not impossible to do so.

As a temporary object (12.2), the result of the + will be destroyed as the last step in the evaluation of the full-expression (1.9/9) that contains it. In this case the full-expression is the throw-expression.

A throw-expression constructs a temporary object (the exception-object) (15.1) (std::runtime_error in this case). All the temporaries in the throw-expression will be destroyed after the exception-object has been constructed. The exception is thrown only once the evaluation of the throw-expression has completed, as the destruction of temporaries is part of this evaluation they will be destroyed before the destruction of automatic variables constructed since the try block was entered (15.2) and before the handler is entered.

The post-condition on runtime_error's constructor is that what() returns something that strcmp considers equal to what c_str() on the passed in argument returns. It is a theoretical possiblility that once the std::string passed as a constructor argument is destroyed, runtime_error's what() could return something different, although it would be a questionable implementation and it would still have to be a null-terminated string of some sort, it couldn't return a pointer to a stale c_str() of a dead string.

Note that the runtime_error exception class makes a copy of the string passed into the constructor. So when you're calling .what() on the exception object, you're not getting back the same exact string instance you passed in.

So to answer your question, the temporary you're asking about gets destroyed "at the semicolon" of the expression that contains it (this is true in both your first and second version of the question), but as I said, this isn't that interesting, because a copy of it was already made.