I have an opened project in Eclipse. I have some special extensions like *.VW,*.RW and many. If I double click those files in Eclipse, it will automatically open in default eclipse text editor.
How can I put the directory (not full path) of the file which opened the script into a variable? I assume this is the same as $1, so I would like file\'s path to yield the same res开发者_运维问答ult w
I have a program, MyApp, where I can open a text file, which works great. The 开发者_开发问答application is created in C# with Visual Studio 2003, .NET 1.1.
Am making an application in Python and I need to provide \"Open with\" menu to user. Currently I am parsing /usr/share/applications/mimeinfo.cashe and ~/.local/share/applications/mimeapps.list but wit
I would like to get the list of \"Open with...\" contextual menu in Windows XP/Vista/7 from Java. From the Windows Registry, I\'ve managed to find a way to get the command to launch applications. But
I am developing an Deskto开发者_JAVA百科p application which organizes and plays movie files. So, I have added the mp4, mov, avi, m4v (mp4, mov, avi, m4v extensions) as document type under Properties o
This question already has answers here: Closed 10 years ago. Possible Duplicate: Filetype association with application (C#)
I wrote an application which will be able to open files of particular extension and show it to users. Now I want the users to be able to just double click the file and have it open with my application
I created a text editor in 开发者_JS百科C# and I use a special file extension for the XML file that my program uses. When I use \"Open With...\" from the Windows context menu, my program doesn\'t read
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