a = 21850开发者_运维技巧0000000 s = 6 f = 2 k = 49 d = k + f + s r = a i = 0 while (r >= d): r = r - d
I would like to represent a value as a 64bit signe开发者_运维百科d long, such that values larger than (2**63)-1 are represented as negative, however Python long has infinite precision. Is there a \'qu
Can someone suggest a fast 2 way encryption algorithm for long ints? My candidates are: AES: the Advanced Encryption Standard specified by NIST FIPS-197.
I want to handle the special case where multiplying two numbers together causes an overflow. The code looks something like this:
Can anyone explain the output of this program and how I can fix it? unsigned long long ns = strtoull(\"123110724001300\", (开发者_如何学Pythonchar **)NULL, 10);
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