I recently faced a strange behavior using the right-shift operator. The following program: #include <cstdio>
Well, a simple question here I am studying some assembly, and converting some assembly routines back to VB.NET
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical andcannot be reasonably answered in its current form. For help clari
I have the following function for reading a big-endian quadword (in a abstract base file I/O class): unsigned long long File::readBigEndQuadWord(){
I\'ve got a code like this in C: unsigned char const data[ ] = {0x0a, 0x1d, 0xf0, 0x07}; I need to extract it such that the final value is:
I have to shift the int one place to the right and return it In Java i can just return n >> 1; Is this possible 开发者_运维技巧in C?
I discovered something odd that I can\'t explain. If someone here can see what or why this is happening I\'d like to know. What I\'m doing is taking an unsigned short containing 12 bits aligned high l
I\'m converting some assembly code to C to be able to use it with the current compiler environment I have to work with.
May I know how can I do PHP >>> ? Such operators is not available in PHP, but is available in Javascript.
If the value after the shift operator is greater than the number of bits in the left-hand operand, the result is
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