The Free structure page on the Haskell wiki defines a function to convert a functor instance into a free monad:
I thought I\'d try the intriguing Representable-functors package to define a Monad and Comonad instance for the functor given by data Pair a = Pair a a which is representable by Bool; as mentioned in
From http://happstack.com/docs/crashcourse/HappstackState.html When I run the server, the peek counter increases by
Quote from here: http://www.haskell.org/haskellwiki/Global_variables If you have a global environment,
I wrote a function in haskell that takes a few parameters like Word32, String (ignore currying) and outputs IO Word32. Now, this is a function in the true sense: for the same inputs, the output will a
The documentation for Control.Monad.List.ListT states that it \"does not yield a monad unless the argument monad is commutative.\"
I am, for some time, experimenting with LLVM, simply because. It does, however, consume more of my time than I thought.
I am parsing binary data out of files using Binary.Get and have something like the following: data FileMessageHeaders = FileMessa开发者_运维问答geHeaders [FileMessageHeader]
I have a Data.Map structure that maps Strings to Stringss. For whatever reason, I want to print the contents of the map in the format key: value using foldrWithKey, like so:
I want to create a couple of computational expressions that would be used to access the database and return a list of items like so (I also have questions in the code comments):
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